Submitted 4 hours ago by otter@lemmy.ca to nostupidquestions@lemmy.world
https://media.piefed.social/posts/9Y/KR/9YKRuOSuZK5h3WP.jpg
For some of these, I estimate the number of items the base and then multiply by the height. Is there a better strategy?
Original post crossposted from !dailygames@lemmy.zip: piefed.social/post/1205620
Guess here: 🔗 estimate-me.aukspot.com/archive/2025-08-29
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Count the visible ones and multiply by pi
I would look at them and pull a number out of my ass.
Empty the cup and then count them all
Find a cup that is similarly shaped and sized, fill it with hazelnuts and then count it manually
This is a 2D image of a cup of hazelnuts. The number is just the ones you can see. The ones you can't see aren't part of the image.
For me, it would be more about figuring out the rough volume. So, like, you look at a hazelnut, it appears to be about a half-inch spherical value. There seem to be about 6 wide across the bottom, so you could assume that the bottom is somewhere around three inches wide. The top is probably closer to about 5 inches wide. And the height is going to be something like 6 inches.
This is also using rough guesstimation from my own personal knowledge of cups.
So with that information I would use what I remember of the cylinder formula, which is pi times diameter times height I think.
And average the two diameters for a four, so you would go four times six times pi is about 75 cubic inches of volume. Each hazelnut uses about 3/4 of an inch of volume so I would guess there are about 100 hazelnuts in the cup.
That being said, the question is not, what is the correct way to guess it, just how would I do it, and this is how I would do it.
I think that this is more or less the approach I would take, but you shouldn't worry about the actual diameter of anything. It's not important, after all - if everything was scaled up twice as big, the answer would be the same. Just call the diameter of the cup a nice round number and then see how the hazelnuts compare to it. In this case I think there's about five hazelnut widths to the glass, so I'm gonna call the glass diameter 50, the nuts 10, and the glass height 80.
You'll need to change your formulae, though. pi*d is the circumference of a circle, but we need the area here, so pi*r*r (and then multiply by height for volume). That gives me 157,050 whateverunits cubed for the volume of the cup. For a sphere it's (4/3)*pi*r*r*r, so 524 for the hazelnuts. Now, I know that spheres don't pack perfectly into a volume, but I don't remember the factor even for optimal packing, so I'm just gonna take a wild guess and say that 70% of the internal volume of the cup is actually occupied by hazelnuts. That gives me... 209 hazelnuts in the cup. Which seems worse than your answer on a gut level, but I can count 86 visible ones so it's maybe actually not bad
And after actually putting my quotes into it, I was horribly wrong, but still, that’s how I would have done it.
All of them are in the cup.
No, I have some in a jar at my house, so it can’t be all of them.
I saw some at the store, but I need to go back and confirm that they are still there
1, all is not a numeric value 2, not all of them are in the cup. Some of them are resting on top of others that are in the cup, but they themselves are outside of the cup’s boundaries.
Weigh 10 hazelnuts, weigh all hazelnuts, do basic math.
Can't math so would do it entirely visually and I would get it wrong but feel happy that I'd picked a number (in this case 215) and been able to move on 🤣
For this one I would count half of the from, half of the top, multiply them, the multiply by 4, the subtract the 10%.
28 front 8 top (28x8x4)×(0.9) = 100.8 ~ 101
Uli@sopuli.xyz 9 minutes ago
None, that’s a jar.