Comment on Drink it, I dare ya

expatriado@lemmy.world ⁨1⁩ ⁨year⁩ ago

• grandkaiser@lemmy.world ⁨1⁩ ⁨year⁩ ago

  Alright, so let’s say this bottle suddenly appeared on your kitchen counter:

  t = 0:

  • The liquid C₂O immediately begins to decompose. Since it’s highly unstable, the bonds between carbon and oxygen atoms start breaking apart, even more rapidly in the presence of air.
  • The immediate breakdown will produce carbon monoxide (CO) and elemental carbon ©.

  t = 0 to t = 0.01 milliseconds: The initial decomposition reaction of C₂O releases a significant amount of heat. The heat from this reaction will cause the wax paper bottle to begin melting almost instantly. This would expose the highly reactive C₂O directly to the air. Since the wax paper is flammable, the intense heat would cause the bottle to ignite, adding burning wax to the mix.

  t = 0.01 milliseconds to t = 0.1 milliseconds:

  • The carbon monoxide (CO) gas and solid carbon particles being produced will come into direct contact with the air. In the presence of oxygen, the carbon monoxide (CO) would start to burn, forming carbon dioxide (CO₂) and releasing even more heat: 2CO + O2 --> 2CO2
  • The wax paper bottle will likely be completely engulfed in flames at this point, burning rapidly due to the intense heat generated by the decomposition of C₂O and the oxidation of CO.

  t = 0.1 milliseconds to t = 1 millisecond:

  • The wax paper, now fully aflame, is contributing to the fire, adding smoke and soot from the combustion of hydrocarbons in the wax.
  • As the heat from the fire builds, any residual liquid C₂O would further vaporize and decompose, intensifying the reaction. The decomposition continues to produce CO and solid carbon, while the surrounding air feeds oxygen to the burning CO, turning it into CO₂.
  • At this stage, the pressure inside the remaining wax paper bottle would become too high, likely causing the bottle to burst in a small explosion, spraying any remaining liquid C₂O into the air.

  t = 1 millisecond to t = 1 second:

  • As the explosion occurs, the now airborne liquid C₂O particles would decompose instantly, reacting with the available oxygen in the air and producing more CO and CO₂. The additional heat generated would cause a fireball to erupt, consuming any remaining wax from the bottle and intensifying the flames.
  • Carbon soot (from the solid carbon produced in the decomposition) would mix with the smoke from the burning wax, forming a thick, black cloud.
  • The surrounding air would become superheated, and the fireball would quickly dissipate as the remaining C₂O fully decomposes and reacts with oxygen.

  (t = 1 second and beyond):

  • The result is a scorched area where the wax paper bottle used to be, surrounded by the remnants of burnt wax, carbon dioxide (CO₂), and solid carbon (soot).
  • The carbon monoxide initially produced would be mostly oxidized into carbon dioxide due to the presence of oxygen, though some trace CO might still linger.
  • Soot and charred remains of the wax bottle would coat the immediate area, while the air would be filled with the smell of burnt wax and carbon.

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  • Hupf@feddit.org ⁨1⁩ ⁨year⁩ ago

    what-if.xkcd.com/6/

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• Eiri@lemmy.ca ⁨1⁩ ⁨year⁩ ago

  Dicarbon monoxide. Wikipedia is shockingly poor in information about it, but “stable” is certainly not the first word I’d use to describe it.

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  • roguetrick@lemmy.world ⁨1⁩ ⁨year⁩ ago

    You could also do something like en.m.wikipedia.org/wiki/Ethylene_oxide but remove the hydrogens and then have the carbons do a triple bond to make pubchem.ncbi.nlm.nih.gov/…/Epoxy-acetylene

    Considering ethylene oxide is already so unstable as fuck though due to its strained structure that it’s used as the main component in thermobaric weapons and this would be even more strained, I don’t know if that would be an improvement.

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  • JackbyDev@programming.dev ⁨1⁩ ⁨year⁩ ago

    Oh, cumulene, I swear on my knees.

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  • consumptionone@lemmy.world ⁨1⁩ ⁨year⁩ ago

    From the third sentence is the wiki page:

    It is, however, so extremely reactive that it is not encountered in everyday life.

    So yeah, not at all stable.

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    • yetAnotherUser@discuss.tchncs.de ⁨1⁩ ⁨year⁩ ago

      But wait, from further down:

      It is stable enough to observe reactions with NO and NO2

      We now have a lower and upper bound for its reactivity at least:

      able to observe reactions with NO and NO2 ≤ Reactivity < encountered in everyday life

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    • Podunk@lemmy.world ⁨1⁩ ⁨year⁩ ago

      I was about to say, you got way too many things that absolutely will bond with that with no hesitation. Thats a very unstable molecule.

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      • nilloc@discuss.tchncs.de ⁨1⁩ ⁨year⁩ ago

        I would thing the plastic lining in that container would probably be high on the bonding list, but I haven’t taken a chemistry class in 24 years.

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    • Aurenkin@sh.itjust.works ⁨1⁩ ⁨year⁩ ago

      Well, it seems Wikipedia was wrong at least about the second half of that sentence

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      • Jolteon@lemmy.zip ⁨1⁩ ⁨year⁩ ago

        To be fair, most people won’t buy this specific drink.

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  • ornery_chemist@mander.xyz ⁨1⁩ ⁨year⁩ ago

    Alternatively for a full octet on every atom, oxiryne, which does not exist and does not have a wiki page. It’s basically acetylene with its arms chopped off and the stumps dislocated, bent back, and stapled together with an oxygen atom.

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    • roguetrick@lemmy.world ⁨1⁩ ⁨year⁩ ago

      pubchem.ncbi.nlm.nih.gov/…/Epoxy-acetylene

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    • Fosheze@lemmy.world ⁨1⁩ ⁨year⁩ ago

      Please describe all chemistry to me as body horror.

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• clutchtwopointzero@lemmy.world ⁨1⁩ ⁨year⁩ ago

  Looks pretty darn reactive

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