Or maybe you just want waffles with 17 squares in them.
Comment on Just one more square bro
red_bull_of_juarez@lemmy.dbzer0.com 1 day agoIsn’t this only true if the outer square’s size is not an integer multiple of the inner square’s size? Meaning, if you have to do this to your waffle iron, you simply chose the dimensions poorly.
deus@lemmy.world 1 day ago
AnarchistArtificer@slrpnk.net 1 day ago
The optimisation objective is to fit n smaller squares (in this case, n=17) into the larger square, whilst minimising the size of the outer square. So that means that in this problem, the dimensions of the outer square isn’t a thing that we’re choosing the dimensions of, but rather discovering its dimensions (given the objective of "minimise the dimensions of the outer square whilst fitting 17 smaller squares inside it)
wolframhydroxide@sh.itjust.works 13 hours ago
Specifically, the optimal area side length of the larger square for any integer n is the square root of n. The closer your larger side length gets to sqrt(n), the more efficient your packing.