Comment on UwU brat mathematician behavior

• Zagorath@aussie.zone ⁨2⁩ ⁨days⁩ ago

  “operative” instead of, uh, something else

  I think they meant “operand”. As in, in the way dy/dx can sometimes be treated as a fraction and dx treated as a value.

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  • Chrobin@discuss.tchncs.de ⁨2⁩ ⁨days⁩ ago

    I think you mean operator. The operand is the target of an operator.

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    • Zagorath@aussie.zone ⁨2⁩ ⁨days⁩ ago

      The operand is the target of an operator

      Correct. Thus, dx is an operand. It’s a thing by which you multiply the rest of the equation (or, in the case of dy/dx, by which you divide the dy).

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      • Chrobin@discuss.tchncs.de ⁨2⁩ ⁨days⁩ ago

        I’d say the $\int dx$ is the operator and the integrand is the operand.

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