Using a sledgehammer to crack a nut

Comments

• Eufalconimorph@discuss.tchncs.de ⁨1⁩ ⁨year⁩ ago

  Well, you’ve got 1. And -1. And sqrt(-1). And the unit pseudoscalars of the Clifford algebras for every number of dimensions.

  So there are a countably infinite number of solutions. Can anyone find a bigger set? Something with an uncountably infinite set of solutions?

  source

  • Rin@lemm.ee ⁨1⁩ ⁨year⁩ ago

    not sure I’m following. there are only two solutions to this. the equation is essentially:

    x² -1 = 0
    x² = 1 
    x = ±√1
    x = ±1
    => x = 1, x = -1
    

    supposing x was √-1:

    (√-1)² -1 = 0
    -1 -1 = 0
    -2 = 0
    

    therefore we can certainly conclude that x ≠ √-1

    source
  • kogasa@programming.dev ⁨1⁩ ⁨year⁩ ago

    There’s only 2. sqrt(-1) isn’t a solution.

    source
• can@sh.itjust.works ⁨1⁩ ⁨year⁩ ago

  Is that Bill Gates?

  source

  • GBU_28@lemm.ee ⁨1⁩ ⁨year⁩ ago

    Yep, the poorer of the two dudes playing lol

    source

    • darcy@sh.itjust.works ⁨1⁩ ⁨year⁩ ago

      sucks to be him

      source