If you were using nonstandard analysis with dx an infinitesimal you could put it outside I guess. Maybe with differential forms too?
Comment on UwU brat mathematician behavior
marcos@lemmy.world 3 days ago
Hum… I don’t think the integral “operator” applies by multiplication.
You can put the dx at the beginning of the integral, but not before it.
OrganicMustard@lemmy.world 3 days ago
marcos@lemmy.world 3 days ago
Switch it with a summation operator and see if it makes sense. The problem isn’t the operation by itself, but the fact that the operator implies an argument application, like a function.
OrganicMustard@lemmy.world 2 days ago
In the case of dx as an infinitesimal it makes sense. You are making a sum of all the values of the function in the integral range and multiplying with a constant dx.
kogasa@programming.dev 3 days ago
In the context of differential forms, an integral expression isn’t complete without an integral symbol and a differential form to be integrated.
LeFrog@discuss.tchncs.de 3 days ago
Physicists be like: whitness me
marcos@lemmy.world 3 days ago
Nobody on your link is treating the integral “operator” as multiplicative.