Comment on xkcd #3094: Mass Spec
Naz@sh.itjust.works 1 week agoF = M×A
So if your F and A are constants (e.g: Where A is the gravity of the Earth) you solve for M.
Also known as a balancing scale.
Magrail works too.
Comment on xkcd #3094: Mass Spec
Naz@sh.itjust.works 1 week agoF = M×A
So if your F and A are constants (e.g: Where A is the gravity of the Earth) you solve for M.
Also known as a balancing scale.
Magrail works too.
remotelove@lemmy.ca 1 week ago
Gravity is not a constant and that would probably matter at the precision that needs to be measured in the given test environment. In any other situation, gravity (or the state of the earths magnetic field) absolutely would not matter.
The precision of F=MA might even be debatable as an accurate formula at these scales… I dunno about that though.
en.m.wikipedia.org/wiki/Gravity_of_Earth
…nasa.gov/…/measuring-earths-magnetism
Naz@sh.itjust.works 1 week ago
Hell yeah, I love scientists 😎
You’re right 👍
I guess this makes me an engineer using FP4 and not FP64