Comment on Or we could do metric time
ElderWendigo@sh.itjust.works 7 months agoIn this scheme, new years day and leap days are not any day of the week or part of any month. They exist outside of the regular calendar as obvious and explicit resets to the remainder problem.
lugal@sopuli.xyz 7 months ago
My point exactly. So the programmer who commented above me is wrong in saying it makes it easier for them
ElderWendigo@sh.itjust.works 7 months ago
No, still easier. They are still part of the year, so you can just count them, put them in their own special no name month if you like, and the logic is still easier than the mess we currently have.
lugal@sopuli.xyz 7 months ago
Computers store the date as “days after January 1st 1970”. So you have a huge number, divide it with 7 and get the day of the week. If there are days that don’t belong to any week, you have to calculate January 1st of that year and substrate it in addition to the steps above. I don’t say it’s not manageable, but it’s not easier
ElderWendigo@sh.itjust.works 6 months ago
They store the number of seconds since the epoch of 1970, but you’re always going to have leap days and even leap seconds. Even if you changed the definition of a second to match the current length of a year, it would be off again relatively soon and you’d need leap seconds again. It’s NEVER going to be as simple as you seem to think it should be. Chaos and complexity is inherent in the whole system.