Look, short of changing Earth’s orbit, something’s not gonna line up no matter what you do. Extra-weekly days are as good a compromise as any in my book.
Comment on Or we could do metric time
lugal@sopuli.xyz 5 months agoWhich breaks “day of week = day modulo 7” if every month starts on Monday and not every month has the same number of days
grue@lemmy.world 5 months ago
lugal@sopuli.xyz 5 months ago
There is also a technological solution, I knew it
sukhmel@programming.dev 5 months ago
Leap day and new year day are supposed to not be a week day in this system
lugal@sopuli.xyz 5 months ago
My point exactly. So the programmer who commented above me is wrong in saying it makes it easier for them
ElderWendigo@sh.itjust.works 5 months ago
In this scheme, new years day and leap days are not any day of the week or part of any month. They exist outside of the regular calendar as obvious and explicit resets to the remainder problem.
lugal@sopuli.xyz 5 months ago
My point exactly. So the programmer who commented above me is wrong in saying it makes it easier for them
ElderWendigo@sh.itjust.works 5 months ago
No, still easier. They are still part of the year, so you can just count them, put them in their own special no name month if you like, and the logic is still easier than the mess we currently have.
lugal@sopuli.xyz 5 months ago
Computers store the date as “days after January 1st 1970”. So you have a huge number, divide it with 7 and get the day of the week. If there are days that don’t belong to any week, you have to calculate January 1st of that year and substrate it in addition to the steps above. I don’t say it’s not manageable, but it’s not easier