The visible part of the spectrum is likely going to be absorbed somewhere far away from the place you’re trying to heat up. Also, I’m not educated enough to tell if there will be further losses of energy
Doesn’t the light turn into heat anyway as soon as it’s absorbed?
sukhmel@programming.dev 8 months ago
CookieOfFortune@lemmy.world 8 months ago
If it’s in a room the visible radiation will still just heat up the room. If you’re using it outdoors and point it away then yeah you’ll have some waste.
sukhmel@programming.dev 8 months ago
Not sure if visible radiation that leaves through a transparent window will still heat up only inside the room, that what I meant. Probably should have phrased it better
FiskFisk33@startrek.website 8 months ago
that’s only true if you shine it out a very large the window
fubbernuckin@lemmy.world 8 months ago
I mean if you want to go that route, we could just say that every speaker, light source, motor, etc is 100% efficient at generating heat because all of its energy output will eventually become heat.
xigoi@lemmy.sdf.org 8 months ago
That is also completely true, but meaningless because heat generation is not the purpose of these devices. However, if you use them in a building heated by a thermostat-controlled electric heater, you’re effectivhly running them for free.
Xatix@lemmy.world 8 months ago
I‘m was using two old servers with folding@home running as space heaters in the winter. I got them for dirt cheap and thought if I convert electricity into heat, I might as well do something good with it. Also nice opportunity to run a minecraft server for the kids during that time.
Xatix@lemmy.world 8 months ago
entropicdrift@lemmy.sdf.org 8 months ago
You double-posted this comment, FYI
PeterPoopshit@lemmy.world 8 months ago
Energy can neither be created nor destroyed so in the grand scheme of things, everything is 100% energy efficient one way or another.
vynlwombat@lemmy.world 8 months ago
I suggest we submit proposals to define “100%” and “efficient” before we design the experiment