Comment on Programmer tries to explain binary search to the police

• Sagifurius@lemm.ee ⁨1⁩ ⁨year⁩ ago

  That’s easy enough to answer, but he really should work on his grammar. In that case you just do 3 groups of three, weigh two of them. If they’re even, the third group is different. Weigh 2 membres of the third group, they’ll either be even or one heavier. Weight the last member against the heavier one from step 2 to see if they’re even or not for your answer.

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  • Mr_Dr_Oink@lemmy.world ⁨1⁩ ⁨year⁩ ago

    Thats 4 uses of the seesaw. It has to be 3.

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    • Sagifurius@lemm.ee ⁨1⁩ ⁨year⁩ ago

      That three dude

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      • Mr_Dr_Oink@lemmy.world ⁨1⁩ ⁨year⁩ ago

        Im sorry when i read weigh two of them i counted it as two separate weighings of two sets of groups. My bad.

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