Meow
Comment on You heard me.
cyberic@discuss.tchncs.de 1 year ago
Quick Proof: Let k be an even number, then (k +1) is odd.
(k +1) + (k+1) = k + 1 + k + 1 = 2k + 2 which will be even.
trimmerfrost@lemm.ee 1 year ago
Comment on You heard me.
cyberic@discuss.tchncs.de 1 year ago
Quick Proof: Let k be an even number, then (k +1) is odd.
(k +1) + (k+1) = k + 1 + k + 1 = 2k + 2 which will be even.
Meow
MBM@lemmings.world 1 year ago
That’s if you add two of the same odd number. The more general proof is basically the same though: let
n
andm
be integers, then2n+1
and2m+1
are odd.(2n+1) + (2m+1) = 2n + 2m + 2 = 2(n+m+1)
which will be even.Pfnic@feddit.ch 1 year ago
This is why I failed at uni. I’m struggling so hard to make sense of such proofs, even if I understand the underlying concepts… :(
bitwolf@lemmy.one 1 year ago
It helped me to lean on the different principals as an example.
The easiest being Principal of Induction. Substitute
k
andm
with 1,3,5,7,9…After going through a few iterations you can see if it holds up enough to keep testing with other principals. (Super simplified).
stebo02@sopuli.xyz 1 year ago
Or you can just like, understand that an odd number is one more than an even number so if you add them together it’s two more than an even number, hence even.
MBM@lemmings.world 1 year ago
Definitely, that’s how I’d explain it in words
lemmyseikai@lemmy.world 1 year ago
Which is the layman’s terms of the proof… I don’t get what your goal is.
Is this a ridiculous formalized statement? Yes, of course it is. Is it a building block for learning to read mathematical works? Yes, of course it is. But that’s the point. We need to practice the trivial to build the scaffolding to tackle the exceptional.
I am not wont to draw conclusions with minimal evidence, but your post seems like you are a malicious reductionist that may be suffering from Dunning Kruger syndrome. I apologize in advance if I have miscategorized you based on this limited sample.
stebo02@sopuli.xyz 1 year ago
I just wanted to show you don’t need any mathematics to understand why this is true.