Comment on If AI was going to advance exponentially I'd of expected it to take off by now.

• Shardikprime@lemmy.world ⁨1⁩ ⁨month⁩ ago

  Man just say you don’t understand functions and that’s it, you don’t have to push it

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  • Clinicallydepressedpoochie@lemmy.world ⁨1⁩ ⁨month⁩ ago

    Tell me how im wrong.

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    • logi@lemmy.world ⁨1⁩ ⁨month⁩ ago

      How about this, this is a real easy one. What type of function is this:

      There is a theorem that “all smooth functions are locally linear”. In other words, most “normal” functions are indistinguishable from a straight line on the graph if you zoom in far enough.

      So that’s not just no than easy one, it is an impossible one.

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      • Clinicallydepressedpoochie@lemmy.world ⁨1⁩ ⁨month⁩ ago

        And yet you want me to believe that because “exponential functions can have a slow build up” its is definitely exponental.

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    • logi@lemmy.world ⁨1⁩ ⁨month⁩ ago

      Or you can just admit you dont have any data to quantify your assertion that AI advancement is exponential growth.

      Ah, that’s a fair argument. LLMs growing exponentially is just an assertion being made and we’re supposed to believe that then the steep growth must be just around the corner.

      But all over this post you’ve got heavily downvoted comments that sound like you are misunderstanding exponential functions rather than doubting that they’re the right model for this.

      We might be on the steep part of an S function right now.

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      • Clinicallydepressedpoochie@lemmy.world ⁨1⁩ ⁨month⁩ ago

        You can read. Read my comments.

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• calcopiritus@lemmy.world ⁨1⁩ ⁨month⁩ ago

  The exponential function has a single horizontal asymptote at y=0. Asymptotes at x=1 and x=-4 would be vertical. Exponential functions have no vertical asymptotes.

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  • Clinicallydepressedpoochie@lemmy.world ⁨1⁩ ⁨month⁩ ago

    I didnt say there are asymtotes at 1 and -4 I said at x=-4, the asymtote can be estimat3d by Y.

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