Well e^iπ=cosπ+isinπ=-1 but an error of 1 isn’t so bad so it’s close enough
Comment on impossible
Jumuta@sh.itjust.works 1 year agoe^(i*Pi) = 0 is cooler
NewSmileadon@lemmy.world 1 year ago
TheBlue22@lemmy.blahaj.zone 11 months ago
That one always fucked me up in my calculus classes
Rentlar@lemmy.ca 1 year ago
might be missing a +1
Jumuta@sh.itjust.works 11 months ago
yesh sry