Well e^iπ=cosπ+isinπ=-1 but an error of 1 isn’t so bad so it’s close enough
Comment on impossible
Jumuta@sh.itjust.works 7 months agoe^(i*Pi) = 0 is cooler
NewSmileadon@lemmy.world 7 months ago
TheBlue22@lemmy.blahaj.zone 7 months ago
That one always fucked me up in my calculus classes
Rentlar@lemmy.ca 7 months ago
might be missing a +1
Jumuta@sh.itjust.works 7 months ago
yesh sry