Comment on Naturally
The result is 𝑦 = ⅟ₓ, right?
No e^x doesn’t have a ‘y’ and so it also acts as a constant.
Oh, I was thinking of it as 𝑦 = 𝑒^𝑥^ or 𝑥 = ln 𝑦, whose derivative in respect to 𝑦 is 𝑥 = 1/𝑦 (for 𝑥 > 0) or 𝑦 = 1/𝑥 (for 𝑦 > 0).
yayaya, or in other cases like multiple independent variables, I’m not sure because it’s been 6 years since I took calculus
The general form would be implicit differentiation! d/dx dx/dy e^x = e^x dx/dy
Papergeist@lemmy.world 1 day ago
No e^x doesn’t have a ‘y’ and so it also acts as a constant.
ChaoticNeutralCzech@feddit.org 1 day ago
Oh, I was thinking of it as 𝑦 = 𝑒^𝑥^ or 𝑥 = ln 𝑦, whose derivative in respect to 𝑦 is 𝑥 = 1/𝑦 (for 𝑥 > 0) or 𝑦 = 1/𝑥 (for 𝑦 > 0).
anothercatgirl@lemmy.blahaj.zone 1 day ago
yayaya, or in other cases like multiple independent variables, I’m not sure because it’s been 6 years since I took calculus
MOCVD@mander.xyz 13 hours ago
The general form would be implicit differentiation! d/dx dx/dy e^x = e^x dx/dy