Comment on How to improve my battery measurement circuit?
nilclass@discuss.tchncs.de 1 year agoYou could probably increase the 82K and 10K resistors to be much bigger
That’s what I thought initially, but this stackoverflow post dissuaded me. The argument there is that the measurement will be wrong, if the input current is not enough to charge the internal cap within the measurement period. But I’ve done some testing now, and measurements done with 820k and 100k agree well with what my voltmeter measures, so I’ll go with this solution!
a fresh alkaline 9V battery is actually 9.6V or more, not 9V.
Indeed! 9.6V * 10k/92k = 1.04V is still below 1.1V, so I should be fine in this case :)
9V battery voltages droop noticeably when under load because of their high internal resistance. Make sure to measure under the same conditions.
This is a good point!
My firmware will be pretty monotonic though, basically:
- wake up
- measure battery
- measure some other sensors (the actual task of the device)
- turn on a transceiver, send all the measurements (including battery voltage)
- turn off transceiver & go to sleep
So, the load should be always the same at step (2).
brendan@mastodon.brendans-bits.com 1 year ago
@nilclass
@WaterWaiver
From the stack exchange post: " 10 kΩ or less source resistance is recommended, otherwise the low pass filter effect of the capacitor with the source resistance becomes a major issue, requiring a longer sampling time for conversion and as a result limiting the maximum frequency."
In other words: a higher source impedance (caused by large resistors) is only going to drastically affect the results when you need to take fast repeated measurements (e.g. an AC source)